2x^2-1750x-390624=0

Solution for 2x^2-1750x-390624=0 equation:

2x^2-1750x-390624=0

a = 2; b = -1750; c = -390624;
Δ = b2-4ac
Δ = -17502-4·2·(-390624)
Δ = 6187492
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6187492}=\sqrt{4*1546873}=\sqrt{4}*\sqrt{1546873}=2\sqrt{1546873}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1750)-2\sqrt{1546873}}{2*2}=\frac{1750-2\sqrt{1546873}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1750)+2\sqrt{1546873}}{2*2}=\frac{1750+2\sqrt{1546873}}{4}
$